Question

find the product of the binomials using the appropriate special product (difference of two squares, square of a binomial sum, or square of a binomial difference).

\\(3x - 2)(3x - 2)\\

Explanation:

Identify the special product form

Using the Special Products knowledge point

$$ (3x - 2)(3x - 2) = (3x - 2)^2 $$

Apply the square of a binomial difference formula

We use the algebraic identity for the square of a binomial difference:

$$ (a - b)^2 = a^2 - 2ab + b^2 $$

Here, we let \(a = 3x\) and \(b = 2\).

Calculate each term of the expanded polynomial

We compute the individual components of the formula:

$$
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$$

Combine the terms to find the final product

We substitute the calculated terms back into the identity:

$$ (3x - 2)^2 = 9x^2 - 12x + 4 $$

Answer:

Find the product of the binomials using the appropriate special product (difference of two squares, square of a binomial sum, or square of a binomial difference).

$$(3x - 2)(3x - 2) =$$

<blank>\(9x^2 - 12x + 4\)</blank>