Question

find the perimeter of each figure. dimensions are in inches. all angles are right angles.

1. (9)

figure with dimensions 20, 6, 10, 26

1. (9)

figure with dimensions 32, 40, 15, 34, 40, 10

Explanation:

Step1: Analyze the perimeter of figure 13

For figure 13, we can use the property that the perimeter of a shape with right - angles is equal to the sum of all its side lengths.
The vertical sides: \(26 + 26=52\)
The horizontal sides: \(20+(20 + 10)+(20+10 - 10)+20=80\)
The total perimeter \(P_{13}=52 + 80=132\)

Step2: Analyze the perimeter of figure 14

For figure 14, we first consider the outer rectangle perimeter and then add the two inner sides (because of the indentation).
The outer rectangle has length \(l = 40\) and width \(w=32\). The perimeter of the outer rectangle (if there was no indentation) is \(2\times(40 + 32)=144\)
The two inner vertical sides (due to the indentation) have a total length of \(15\times2 = 30\)
The total perimeter \(P_{14}=144+30=174\)

Answer:

The perimeter of figure 13 is \(132\) inches and the perimeter of figure 14 is \(174\) inches.