QUESTION IMAGE
Question
find the perimeter and area of each rectangle or square.
find the unknown side length.
solve.
7 kaya is wallpapering one wall of her room. the wall is 10 ft
long and 8 ft tall. how many square feet of wallpaper will
kaya need?
8 mias room is 12 ft long and 10 ft wide. she wants to put
a border at the top of the walls. how many feet of border does
she need?
9 a rectangular wall measures 15 ft along the floor. the area of
the wall is 180 ft². what is the height of the wall?
10 corey is tiling a rectangular bathroom that is 6 ft by 8 ft.
each tile covers 2 ft². how many tiles will he need?
Step1: Calculate perimeter and area for rectangle (length \(l = 5\)cm, width \(w=3\)cm)
Perimeter formula \(P = 2(l + w)\), so \(P=2(5 + 3)=16\)cm. Area formula \(A=l\times w\), so \(A = 5\times3 = 15\)cm².
Step2: Calculate perimeter and area for square (side \(s = 3\)cm)
Perimeter formula \(P = 4s\), so \(P=4\times3 = 12\)cm. Area formula \(A=s^{2}\), so \(A=3^{2}=9\)cm².
Step3: Calculate perimeter and area for rectangle (length \(l = 8\)cm, width \(w = 5\)cm)
Perimeter formula \(P = 2(l + w)\), so \(P=2(8 + 5)=26\)cm. Area formula \(A=l\times w\), so \(A=8\times5 = 40\)cm².
Step4: Find unknown side \(b\) of rectangle (\(A = 18\)cm², \(l = 6\)cm)
Using \(A=l\times b\), then \(b=\frac{A}{l}=\frac{18}{6}=3\)cm.
Step5: Find unknown side \(h\) of rectangle (\(A = 14\)cm², \(l = 7\)cm)
Using \(A=l\times h\), then \(h=\frac{A}{l}=\frac{14}{7}=2\)cm.
Step6: Find side \(s\) of square (\(A = 49\)cm²)
Using \(A=s^{2}\), then \(s=\sqrt{49}=7\)cm.
Step7: Calculate area of wall (\(l = 10\)ft, \(h = 8\)ft)
Using \(A=l\times h\), \(A=10\times8 = 80\)ft².
Step8: Calculate perimeter of room (\(l = 12\)ft, \(w = 10\)ft)
Using \(P = 2(l + w)\), \(P=2(12 + 10)=44\)ft.
Step9: Find height \(h\) of wall (\(A = 180\)ft², \(l = 15\)ft)
Using \(A=l\times h\), then \(h=\frac{A}{l}=\frac{180}{15}=12\)ft.
Step10: Calculate number of tiles
Area of bathroom \(A = 6\times8=48\)ft². Number of tiles \(n=\frac{48}{2}=24\).
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- \(P = 16\)cm, \(A = 15\)cm²
- \(P = 12\)cm, \(A = 9\)cm²
- \(P = 26\)cm, \(A = 40\)cm²
- \(b = 3\)cm
- \(h = 2\)cm
- \(s = 7\)cm
- \(80\)ft²
- \(44\)ft
- \(12\)ft
- \(24\) tiles