find the numerical value of the expression if $x = 1$ and $y = 4$.

\0.437x^2 + 0.77y^2\

the numerical value of the expression is $\square$.

Question

find the numerical value of the expression if $x = 1$ and $y = 4$.

\0.437x^2 + 0.77y^2\

the numerical value of the expression is $\square$.

Accepted Answer

{ "quality": "clear", "question_count": 1, "skills_matched": [ "step_cot", "blank_filling_formatter", "explain_then_answer", "quick" ], "needs_drawing": false, "concepts_used": [ "Evaluating Expressions", "Order of Operations" ], "new_concepts": [], "current_concepts": [ "Evaluating Expressions", "Order of Operations" ] } ## Substitute the given values into the expression $$ 0.437(1)^2 + 0.77(4)^2 $$ ## Evaluate the exponential terms $$ \begin{aligned} 1^2 &= 1 \ 4^2 &= 16 \end{aligned} $$ ## Perform multiplication and addition $$ \begin{aligned} 0.437(1) + 0.77(16) &= 0.437 + 12.32 \ &= 12.757 \end{aligned} $$ Find the numerical value of the expression if $x = 1$ and $y = 4$. $0.437x^2 + 0.77y^2$ The numerical value of the expression is 12.757. { "subject": "Mathematics", "question_type": "Fill-in-the-blank", "knowledge_point": [ "Mathematics", "Algebra", "Evaluating Expressions" ] }

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Question

Explanation:

Substitute the given values into the expression

Evaluate the exponential terms

Perform multiplication and addition

Answer: