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Question
find the measures of the angles of a triangle with angles that are in the ratio of 3:4:5. also, what kind of triangle is it? after you pick your answer press go. a b c d e 30, 40, 50; acute triangle
Step1: Set up the equation
Let the angles be \(3x\), \(4x\), and \(5x\). Since the sum of angles in a triangle is \(180^{\circ}\), we have \(3x + 4x+5x=180^{\circ}\).
Step2: Solve for \(x\)
Combine like - terms: \(12x = 180^{\circ}\). Then \(x=\frac{180^{\circ}}{12}=15^{\circ}\).
Step3: Find the measures of the angles
- First angle: \(3x = 3\times15^{\circ}=45^{\circ}\)
- Second angle: \(4x = 4\times15^{\circ}=60^{\circ}\)
- Third angle: \(5x = 5\times15^{\circ}=75^{\circ}\)
Step4: Classify the triangle
Since all angles (\(45^{\circ}\), \(60^{\circ}\), \(75^{\circ}\)) are less than \(90^{\circ}\), it is an acute triangle.
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The measures of the angles are \(45^{\circ}\), \(60^{\circ}\), and \(75^{\circ}\), and it is an acute triangle.