QUESTION IMAGE
Question
2
find the exact value of x and y in the
following special right triangle.
x =
y =
Step1: Identify triangle type
30-60-90 right triangle, sides ratio $1:\sqrt{3}:2$
Step2: Relate given side to ratio
Adjacent to 60°: 2 = longer leg = $\sqrt{3} \times$ shorter leg
Step3: Find shorter leg (x)
$x = \frac{2}{\sqrt{3}} = \frac{2\sqrt{3}}{3}$
Step4: Find hypotenuse (y)
$y = 2x = 2 \times \frac{2\sqrt{3}}{3} = \frac{4\sqrt{3}}{3}$
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$x = \frac{2\sqrt{3}}{3}$, $y = \frac{4\sqrt{3}}{3}$