Question

find the equation of a trend line using (-8, 22) and (3, 0) as anchor points.
y = ?x +

Explanation:

Step1: Calculate slope

Slope $m = \frac{y_2-y_1}{x_2-x_1} = \frac{0-22}{3-(-8)} = \frac{-22}{11} = -2$

Step2: Solve for intercept

Substitute $m=-2$, $(3,0)$ into $y=mx+b$:
$0 = -2(3) + b \implies b = 6$

Answer:

$y = -2x +6$