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find the equation of the line that is perpendicular to \\(y = 6x - 2\\)…

Question

find the equation of the line that is perpendicular to \\(y = 6x - 2\\) and contains the point \\((6,-2)\\).

\\y = -\frac{?}{\box}x + \box\\

Explanation:

Find the slope of the perpendicular line

$$ LATEXBLOCK0 $$

Solve for the y-intercept

$$ LATEXBLOCK1 $$

Write the final equation

$$ y = -\frac{1}{6}x - 1 $$

Answer:

Find the equation of the line that is perpendicular to \(y = 6x - 2\) and contains the point \((6,-2)\).

\(y = -\frac{\text{1}}{\text{6}}x + \text{-1}\)