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find the equation of the line that is parallel to \\(y = -6x + 3\\) and…

Question

find the equation of the line that is parallel to \\(y = -6x + 3\\) and contains the point \\((-2,16)\\).

\\(y = ?x + \square\\)

Explanation:

Identify the slope of the parallel line

$$ LATEXBLOCK0 $$

Use the point-slope formula to find the equation

$$ LATEXBLOCK1 $$

Convert to slope-intercept form

$$ LATEXBLOCK2 $$

Answer:

Find the equation of the line that is parallel to \(y = -6x + 3\) and contains the point \((-2,16)\).

\(y =\) <blank>\(-6\)</blank>\(x +\) <blank>\(4\)</blank>