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find the equation of the line that goes through the points (-3,1) and (…

Question

find the equation of the line that goes through the points (-3,1) and (2,1). what is the slope? m = what is the y - intercept? y=mx + b check it! final answer

Explanation:

Step1: Calculate the slope

The slope formula is $m=\frac{y_2 - y_1}{x_2 - x_1}$. Let $(x_1,y_1)=(-3,1)$ and $(x_2,y_2)=(2,1)$. Then $m=\frac{1 - 1}{2-(-3)}=\frac{0}{5}=0$.

Step2: Find the y - intercept

The equation of a line is $y = mx + b$. We know $m = 0$. Using the point $(x,y)=(2,1)$ (we could use either point), substitute into the equation: $1=0\times2 + b$, so $b = 1$.

Step3: Write the equation of the line

Since $m = 0$ and $b = 1$, the equation of the line is $y=0x + 1$ or simply $y = 1$.

Answer:

The slope $m = 0$, the y - intercept $b = 1$, and the equation of the line is $y=1$.