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find ef. image of right triangle def with right angle at e, leg de labe…

Question

find ef.
image of right triangle def with right angle at e, leg de labeled \\(\sqrt{70}\\), angle at d labeled 29°
write your answer as an integer or as a decimal rounded to the nearest tenth.
ef = \\(\square\\)

Explanation:

Step1: Identify the trigonometric ratio

In right triangle \( DEF \) (right - angled at \( E \)), we know the length of the adjacent side to the angle \( \angle D = 29^{\circ} \) (which is \( DE=\sqrt{70} \)) and we want to find the length of the opposite side \( EF \) with respect to \( \angle D \). The trigonometric ratio that relates the opposite side and the adjacent side of an angle in a right triangle is the tangent function. The formula for the tangent of an angle \( \theta \) in a right triangle is \( \tan\theta=\frac{\text{opposite}}{\text{adjacent}} \).

Step2: Apply the tangent formula

For \( \angle D = 29^{\circ} \), \( \text{opposite}=EF \) and \( \text{adjacent} = DE=\sqrt{70} \). So we have \( \tan(29^{\circ})=\frac{EF}{\sqrt{70}} \). To find \( EF \), we can rearrange the formula: \( EF=\sqrt{70}\times\tan(29^{\circ}) \).

First, calculate the value of \( \sqrt{70}\approx8.3666 \) and \( \tan(29^{\circ})\approx0.5543 \). Then multiply these two values: \( EF\approx8.3666\times0.5543\approx4.6 \) (rounded to the nearest tenth).

Answer:

\( 4.6 \)