Question

find the domain of the function.
$f(x)=\sqrt{\frac{6}{3+x}}$
write your answer as an interval or union of intervals.

Explanation:

Step1: Ensure radicand is non-negative

$\frac{6}{3+x} \geq 0$
Since 6 > 0, denominator must be positive: $3+x > 0$

Step2: Solve inequality for x

$x > -3$

Answer:

$(-3, \infty)$