Question

find the domain of the function.

$u(x)=sqrt{-x}-3$

write your answer as an inequality.
or, you may instead click on \empty set\ or \all reals\ as the answer.

Explanation:

Step1: Set the expression under square - root non - negative

For the function $u(x)=\sqrt{-x - 3}$, we need $-x - 3\geq0$.

Step2: Solve the inequality for $x$

Add $x$ to both sides of $-x - 3\geq0$, we get $- 3\geq x$, which is equivalent to $x\leq - 3$.

Answer:

$x\leq - 3$