find the distance, d, of $ \overline { a b } $.
$ a = ( - 7, - 7 ) \quad b = ( - 3, - 1 ) $
$ d = $
$ d = \sqrt { ( x _ { 2 } - x _ { 1 } ) ^ { 2 } + ( y _ { 2 } - y _ { 1 } ) ^ { 2 } } $
round to the nearest tenth

Question

Accepted Answer

# Explanation:
## Step1: Identify coordinates
Let $A(x_1,y_1)=(-7,-7)$ and $B(x_2,y_2)=(-3,-1)$.
## Step2: Substitute into distance formula
Substitute into $d = \sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}$.
$$
\begin{align*}
d&=\sqrt{(-3-(-7))^2+(-1 - (-7))^2}\
&=\sqrt{(-3 + 7)^2+(-1+7)^2}\
&=\sqrt{(4)^2+(6)^2}\
&=\sqrt{16 + 36}\
&=\sqrt{52}
\end{align*}
$$
## Step3: Calculate and round
$\sqrt{52}\approx7.2$ (rounded to the nearest tenth).

# Answer:
$7.2$

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QUESTION IMAGE

Question

Explanation:

Step1: Identify coordinates

Step2: Substitute into distance formula

Step3: Calculate and round

Answer: