Question

find the distance between the two points rounding to the nearest tenth (if necessary). (3, 2) and (6, 0)

Explanation:

Step1: Recall distance formula

The distance \( d \) between two points \((x_1, y_1)\) and \((x_2, y_2)\) is given by \( d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \).
Here, \( x_1 = 3 \), \( y_1 = 2 \), \( x_2 = 6 \), \( y_2 = 0 \).

Step2: Substitute values into formula

First, calculate \( x_2 - x_1 = 6 - 3 = 3 \) and \( y_2 - y_1 = 0 - 2 = -2 \).
Then, square these differences: \( (3)^2 = 9 \) and \( (-2)^2 = 4 \).
Add the squared differences: \( 9 + 4 = 13 \).
Take the square root: \( d = \sqrt{13} \approx 3.6 \) (rounded to the nearest tenth).

Answer:

\( 3.6 \)