Question

find the distance between the two points rounding to the nearest tenth (if necessary).\\((-6, -4)\\) and \\((-4, 2)\\)

Explanation:

Step1: Recall distance formula

The distance $d$ between two points $(x_1,y_1)$ and $(x_2,y_2)$ is $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Step2: Substitute given points

Let $(x_1,y_1)=(-6,-4)$ and $(x_2,y_2)=(-4,2)$.
$d=\sqrt{(-4-(-6))^2+(2-(-4))^2}=\sqrt{(2)^2+(6)^2}$

Step3: Calculate squared terms

$\sqrt{4+36}=\sqrt{40}$

Step4: Compute and round

$\sqrt{40}\approx6.3$

Answer:

6.3