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Question
find the derivative of the function
$g(x)=(x^{2}+x - 1)e^{x}$
$g(x)=$
note: you are in the reduced scoring period. all work counts for 85% of the original.
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Step1: Apply the product rule
The product rule states that if \(y = f(x)g(x)\), then \(y^\prime=f^\prime(x)g(x)+f(x)g^\prime(x)\). Let \(f(x)=x^{2}+x - 1\) and \(g(x)=e^{x}\). First, find \(f^\prime(x)\):
And \(g^\prime(x)=\frac{d}{dx}(e^{x})=e^{x}\)
Step2: Substitute into the product rule formula
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\(g^\prime(x)=e^{x}(x^{2}+3x)\)