QUESTION IMAGE
Question
find the derivative of ( f(x) ).
( f(x)=-4 e^{-3 x}-3 e^{-4 x} )
( f^{prime}(x)= )
Step1: Apply derivative rules
The derivative of $e^{ax}$ is $ae^{ax}$ (by chain rule).
Step2: Differentiate term - by - term
For $-4e^{-3x}$:
Using the rule, the derivative is $-4\times(-3)e^{-3x}=12e^{-3x}$.
For $-3e^{-4x}$:
Using the rule, the derivative is $-3\times(-4)e^{-4x}=12e^{-4x}$.
Step3: Combine results
$f^{\prime}(x)=12e^{-3x}+12e^{-4x}$.
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$12e^{-3x}+12e^{-4x}$