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Question
find the common ratio \\(r\\) for the geometric sequence and use \\(r\\) to find the next three terms.
- \\(972, 324, 108, 36, \dots\\)
first, identify each term in the sequence. for this sequence,
\\(f(1) = 972\\), \\(f(2) = 324\\), \\(f(3) = 108\\), and \\(f(4) = 36\\)
then, find the common ratio \\(r\\).
\\(r = \frac{324}{972} = \frac{1}{3}\\)
lastly, use \\(f(n) = f(n - 1) \cdot r\\) with \\(r = \text{___}\\) to find \\(f(5)\\), \\(f(6)\\), and \\(f(7)\\).
\\(f(5) = f(4) \cdot \text{___}\\)
\\(f(5) = \text{_} \cdot \text{_}\\)
\\(f(5) = \text{___}\\)
\\(f(6) = f(5) \cdot \text{___}\\)
\\(f(6) = \text{_} \cdot \text{_}\\)
\\(f(6) = \text{___}\\)
\\(f(7) = f(6) \cdot \text{___}\\)
\\(f(7) = \text{_} \cdot \text{_}\\)
\\(f(7) = \text{___}\\)
Calculate the common ratio
Calculate the fifth term
Calculate the sixth term
Calculate the seventh term
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Find the common ratio \(r\) for the geometric sequence and use \(r\) to find the next three terms.
- \(972, 324, 108, 36, \dots\)
First, identify each term in the sequence. For this sequence,
\(f(1) =\) <blank>972</blank>, \(f(2) =\) <blank>324</blank>, \(f(3) =\) <blank>108</blank>, and \(f(4) =\) <blank>36</blank>.
Then, find the common ratio \(r\).
\(r = \frac{324}{972} =\) <blank>\(\frac{1}{3}\)</blank>
Lastly, use \(f(n) = f(n-1) \cdot r\) with \(r =\) <blank>\(\frac{1}{3}\)</blank> to find \(f(5)\), \(f(6)\), and \(f(7)\).
\(f(5) = f(4) \cdot\) <blank>\(\frac{1}{3}\)</blank>
\(f(5) =\) <blank>36</blank> \(\cdot\) <blank>\(\frac{1}{3}\)</blank>
\(f(5) =\) <blank>12</blank>
\(f(6) = f(5) \cdot\) <blank>\(\frac{1}{3}\)</blank>
\(f(6) =\) <blank>12</blank> \(\cdot\) <blank>\(\frac{1}{3}\)</blank>
\(f(6) =\) <blank>4</blank>
\(f(7) = f(6) \cdot\) <blank>\(\frac{1}{3}\)</blank>
\(f(7) =\) <blank>4</blank> \(\cdot\) <blank>\(\frac{1}{3}\)</blank>
\(f(7) =\) <blank>\(\frac{4}{3}\)</blank>