Question

1. find the area of a trapezoid with bases 10 m and 18 m and a height of 6 m. a) 84 m² b) 70 m² c) 60 m² d) 96 m²
2. find the circumference of a circle with a diameter of 12 in. (use π≈3.14) a) 37.68 in b) 40.12 in c) 42.25 in d) 43.96 in
3. find the area of a circle with a radius of 5 cm. (use π≈3.14) a) 78.5 cm² b) 31.4 cm² c) 25.1 cm² d) 60.2 cm²
4. find the midpoint of a segment with endpoints a(-4, 2) and b(6, 8). a) (1, 3) b) (-1, 5) c) (1, 5) d) (3, 7)
5. the midpoint of a segment is m(4, -2), and one endpoint is a(6, 3). find the other endpoint b. a) (2, -7) b) (1, 4) c) (-2, -7) d) (5, -5)

Explanation:

6.

Step1: Recall trapezoid area formula

The formula for the area of a trapezoid is $A=\frac{(b_1 + b_2)h}{2}$, where $b_1$ and $b_2$ are the bases and $h$ is the height. Given $b_1 = 10$ m, $b_2=18$ m and $h = 6$ m.

Step2: Substitute values into formula

$A=\frac{(10 + 18)\times6}{2}=\frac{28\times6}{2}=84$ $m^{2}$.

Step1: Recall circle - circumference formula

The formula for the circumference of a circle is $C=\pi d$, where $d$ is the diameter. Given $d = 12$ in and $\pi\approx3.14$.

Step2: Substitute value into formula

$C=3.14\times12 = 37.68$ in.

Step1: Recall circle - area formula

The formula for the area of a circle is $A=\pi r^{2}$, where $r$ is the radius. Given $r = 5$ cm and $\pi\approx3.14$.

Step2: Substitute value into formula

$A=3.14\times5^{2}=3.14\times25 = 78.5$ $cm^{2}$.

Answer:

A. $84$ $m^{2}$

7.