Question

find the area of this trapezoid.
11 m
3 m
7 m
area of a
trapezoid
$a = \frac { 1 } { 2 } h ( b _ { 1 } + b _ { 2 } )$
$a = square? m ^ { 2 }$

Explanation:

Step1: Identify the values of \(b_1\), \(b_2\), and \(h\)

From the trapezoid, \(b_1 = 11m\), \(b_2 = 7m\), \(h = 3m\)

Step2: Substitute the values into the formula

\(A=\frac{1}{2}h(b_1 + b_2)=\frac{1}{2}\times3\times(11 + 7)\)

Step3: Calculate the sum inside the parentheses

\(11+7 = 18\)
So \(A=\frac{1}{2}\times3\times18\)

Step4: Calculate \(\frac{1}{2}\times18\)

\(\frac{1}{2}\times18 = 9\)
Then \(A=9\times3\)

Step5: Multiply to get the final result

\(9\times3=27\)

Answer:

\(27\)