Question

(a) find the area of the following (in square units).
the light rectangle (on the top):
the dark rectangle (on the bottom):
(b) give the area of the entire figure (in square units) in two different ways.
as a sum of two areas:
as a product of the length and width:

Explanation:

Step1: Calculate top rectangle area

Area = length × width = $3×5 = 15$

Step2: Calculate bottom rectangle area

Area = length × width = $3×x = 3x$

Step3: Sum of two areas for total

Total area = $15 + 3x$

Step4: Product of total length and width

Total length = $5 + x$, width = 3. Area = $3(5 + x)$

Answer:

(a) The light rectangle: 15
The dark rectangle: $3x$
(b) As a sum of two areas: $15 + 3x$
As a product of the length and width: $3(5 + x)$