Question

find the area of each rectangle. what is the area of rectangle 2? area = length x width rectangle 1 40 cm2 rectangle 2 ? cm2 rectangle 3 cm2 total area cm2

Explanation:

Step1: Determine length of Rectangle 2

From Rectangle 1, area = 40 cm², width = 4 cm. So length of Rectangle 1 (and also the total height for Rectangle 2's length) is $length = \frac{area}{width} = \frac{40}{4} = 10$ cm. But Rectangle 2 has a part overlapping (4 cm), so its length is $10 - 4 = 6$ cm? Wait, no, looking at the diagram, Rectangle 2 has width 2 cm and length? Wait, maybe better: Wait, the formula is area = length × width. Wait, maybe I misread. Wait, Rectangle 2: the height? Wait, no, let's look again. Wait, the overlapping square is 4x4. Rectangle 1: 10 cm (height) and 4 cm (width), area 40. Rectangle 2: width 2 cm, and height? Wait, maybe the length of Rectangle 2 is 10 cm? No, wait, the overlapping is 4 cm, so maybe Rectangle 2's length is 10 cm? Wait, no, the diagram: Rectangle 2 is a vertical rectangle with width 2 cm, and height equal to the height of Rectangle 1, which is 10 cm? Wait, no, maybe I made a mistake. Wait, no, let's check the overlapping. Wait, the middle square is 4x4. So Rectangle 1: 10 cm (height) × 4 cm (width) = 40, correct. Rectangle 2: width 2 cm, and height? Wait, maybe the height of Rectangle 2 is 10 cm? No, that can't be. Wait, no, maybe the length of Rectangle 2 is (10 - 4) + 4? No, wait, maybe the length of Rectangle 2 is 10 cm? Wait, no, let's re-express. Wait, the formula is area = length × width. For Rectangle 2, width is 2 cm, and length: looking at the diagram, the total height is 10 cm, same as Rectangle 1. Wait, but there's an overlapping square of 4x4. Wait, maybe Rectangle 2's length is 10 cm? No, that would make area 2×10=20, but maybe not. Wait, no, maybe I misread the dimensions. Wait, the problem says "Find the area of each rectangle. What is the area of rectangle 2? Area = length × width. Rectangle 1: 40 cm² (which is 10×4). Rectangle 2: width 2 cm, and length: let's see, the height of Rectangle 2 is 10 cm? Wait, no, the overlapping square is 4 cm, so maybe the length of Rectangle 2 is 10 cm? Wait, no, maybe the length is 10 cm, width 2 cm, so area is 2×10=20? Wait, but let's check again. Wait, the diagram: Rectangle 1 is 10 cm (height) and 4 cm (width). Rectangle 2 is a vertical rectangle with width 2 cm, and height equal to the height of Rectangle 1, which is 10 cm? Wait, but there's a square in the middle (4x4) overlapping. Wait, maybe the length of Rectangle 2 is 10 cm, so area is 2×10=20. Wait, but let's confirm. Alternatively, maybe the length of Rectangle 2 is (10 - 4) + 4? No, that's 10. Wait, maybe I'm overcomplicating. The formula is area = length × width. For Rectangle 2, width is 2 cm, and length: looking at the diagram, the height is 10 cm (same as Rectangle 1), so length is 10 cm. So area = 2 × 10 = 20? Wait, but maybe the length is different. Wait, no, let's see: Rectangle 1: 10 cm (height) × 4 cm (width) = 40. Rectangle 2: width 2 cm, height 10 cm? Then area is 2×10=20. Alternatively, maybe the height of Rectangle 2 is 10 cm, so yes. So step 1: identify length and width of Rectangle 2. Width is 2 cm, length is 10 cm (same as Rectangle 1's height). Step 2: calculate area.

Step1: Identify dimensions of Rectangle 2

Width of Rectangle 2: $2$ cm.
Length of Rectangle 2: From Rectangle 1, height is $10$ cm (since area = 40 = 10×4), so length of Rectangle 2 is $10$ cm.

Step2: Calculate area of Rectangle 2

Using formula $Area = length \times width$:
$Area = 10 \times 2 = 20$ cm².

Answer:

20