find the area of each circle.
(use 3.14 for $\pi$.)

1)
diameter = 20 ft

2)
diameter = 53 yd

3)
diameter = 9 in

Question

find the area of each circle.
(use 3.14 for $\pi$.)

1)
diameter = 20 ft

2)
diameter = 53 yd

3)
diameter = 9 in

Accepted Answer

{ "quality": "clear", "question_count": 3, "skills_matched": [ "step_cot", "table_formatter", "explain_then_answer", "tutor", "mastery_adaptive_brevity" ], "needs_drawing": false, "concepts_used": [ "Circle Diameter and Radius", "Circle Area Calculation" ], "new_concepts": [], "current_concepts": [ "Circle Diameter and Radius", "Circle Area Calculation" ] } ## Find the radius of each circle Using the *Circle Diameter and Radius* knowledge point $$ \begin{aligned} &r_1 = \frac{20\text{ ft}}{2} = 10\text{ ft}\ &r_2 = \frac{53\text{ yd}}{2} = 26.5\text{ yd}\ &r_3 = \frac{9\text{ in}}{2} = 4.5\text{ in} \end{aligned} $$ ## Calculate the area of the first circle Using the *Circle Area Calculation* knowledge point $$ \begin{aligned} &A_1 = 3.14 \times (10\text{ ft})^2\ &A_1 = 3.14 \times 100\text{ ft}^2\ &A_1 = 314\text{ ft}^2 \end{aligned} $$ ## Calculate the area of the second circle Using the *Circle Area Calculation* knowledge point $$ \begin{aligned} &A_2 = 3.14 \times (26.5\text{ yd})^2\ &A_2 = 3.14 \times 702.25\text{ yd}^2\ &A_2 = 2205.065\text{ yd}^2 \end{aligned} $$ ## Calculate the area of the third circle Using the *Circle Area Calculation* knowledge point $$ \begin{aligned} &A_3 = 3.14 \times (4.5\text{ in})^2\ &A_3 = 3.14 \times 20.25\text{ in}^2\ &A_3 = 63.585\text{ in}^2 \end{aligned} $$ | No. | Answer | |---|---| | 1 | $314\text{ ft}^2$ | | 2 | $2205.065\text{ yd}^2$ | | 3 | $63.585\text{ in}^2$ | { "subject": "Mathematics", "question_type": "Multi-part", "knowledge_point": [ "Mathematics", "Geometry", "Circle Area Calculation" ] }

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QUESTION IMAGE

Question

Explanation:

Find the radius of each circle

Calculate the area of the first circle

Calculate the area of the second circle

Calculate the area of the third circle

Answer:

No.	Answer
2	\(2205.065\text{ yd}^2\)
3	\(63.585\text{ in}^2\)