Question

find $3f^{-1}(0) + g^{-1}(-18)$.\
\

$x$	$f(x)$	$g(x)$	\
---	---	---	\
$4$	$-18$	$-19$	\
$0$	$18$	$-18$	\
$-20$	$4$	$15$	\
$13$	$12$	$17$	\
$5$	$0$	$-20$	\
$-11$	$17$	$-3$	\
$8$	$-15$	$10$

Explanation:

Step1: Find \( f^{-1}(0) \)

To find \( f^{-1}(0) \), we need to find the \( x \)-value such that \( f(x) = 0 \). Looking at the table, when \( x = 5 \), \( f(x) = 0 \). So, \( f^{-1}(0) = 5 \).

Step2: Find \( g^{-1}(-18) \)

To find \( g^{-1}(-18) \), we need to find the \( x \)-value such that \( g(x) = -18 \). Looking at the table, when \( x = 0 \), \( g(x) = -18 \). So, \( g^{-1}(-18) = 0 \).

Step3: Calculate \( 3f^{-1}(0) + g^{-1}(-18) \)

Substitute the values we found: \( 3 \times 5 + 0 = 15 + 0 = 15 \).

Answer:

\( 15 \)