Question

fill in the table using this function rule.
y = 6x - 2
x | y
-5 |
-1 |
0 |
1 |

Explanation:

Step1: Substitute \( x = -5 \) into \( y = 6x - 2 \)

\( y = 6\times(-5) - 2 = -30 - 2 = -32 \)

Step2: Substitute \( x = -1 \) into \( y = 6x - 2 \)

\( y = 6\times(-1) - 2 = -6 - 2 = -8 \)

Step3: Substitute \( x = 0 \) into \( y = 6x - 2 \)

\( y = 6\times0 - 2 = 0 - 2 = -2 \)

Step4: Substitute \( x = 1 \) into \( y = 6x - 2 \)

\( y = 6\times1 - 2 = 6 - 2 = 4 \)

Answer:

When \( x = -5 \), \( y = -32 \); when \( x = -1 \), \( y = -8 \); when \( x = 0 \), \( y = -2 \); when \( x = 1 \), \( y = 4 \)

The completed table (rows in order of \( x = -5, -1, 0, 1 \)) has \( y \)-values: \(-32\), \(-8\), \(-2\), \(4\)