Question

fill in the table using this function rule: $y = -5x - 2$

$x$	$y$
$0$	$square$
$1$	$square$
$2$	$square$

Explanation:

Step1: Substitute \( x = -1 \) into \( y = -5x - 2 \)

\( y = -5\times(-1) - 2 = 5 - 2 = 3 \)

Step2: Substitute \( x = 0 \) into \( y = -5x - 2 \)

\( y = -5\times0 - 2 = 0 - 2 = -2 \)

Step3: Substitute \( x = 1 \) into \( y = -5x - 2 \)

\( y = -5\times1 - 2 = -5 - 2 = -7 \)

Step4: Substitute \( x = 2 \) into \( y = -5x - 2 \)

\( y = -5\times2 - 2 = -10 - 2 = -12 \)

Answer:

When \( x = -1 \), \( y = 3 \); when \( x = 0 \), \( y = -2 \); when \( x = 1 \), \( y = -7 \); when \( x = 2 \), \( y = -12 \)

So the completed table is:

\( x \)	\( y \)
0	-2
1	-7
2	-12