Question

fill in the boxes to add the expressions.
(2n + 2.95) + (4.333n + 2.111) = (2n + _) + (2.95 + _)
= ___
(2n + 2.95) + (4.333n + 2.111) = (2n + \boxed{4.333}) + (2.95 + \boxed{2.111})
= \boxed{}
(simplify your answer. use integers or decimals for any numbers in the expression.)

Explanation:

Step1: Identify like terms for grouping

We use the commutative and associative properties of addition to group like terms. The terms with \(n\) are \(2n\) and \(4.333n\), and the constant terms are \(2.95\) and \(2.111\). So, we group \(2n\) with \(4.333n\) and \(2.95\) with \(2.111\).
\((2n + 2.95)+(4.333n + 2.111)=(2n + 4.333n)+(2.95 + 2.111)\)

Step2: Fill in the boxes

From the above step, the first box (with the \(n\)-term) should be \(4.333n\) and the second box (with the constant term) should be \(2.111\).

Answer:

First box: \(4.333n\), Second box: \(2.111\)