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Question
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the access code to a houses security system consists of four digits.
how many different codes are available if the first digit cannot be 0 and no digit can be repeated?
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the sum of the probabilities of every possible outcome in a probability experiment is always 1. the probability distribution below list the probabilities of every possible outcome in a particular probability experiment.
determine the missing probability value for the probability distribution.
Step1: Analyze the first digit
The first digit cannot be 0, so there are 9 choices (1 - 9).
Step2: Analyze the second digit
Since no digit can be repeated, after choosing the first digit, there are 9 remaining digits (0 and the 8 non - chosen non - zero digits).
Step3: Analyze the third digit
After choosing the first two digits, there are 8 remaining digits.
Step4: Analyze the fourth digit
After choosing the first three digits, there are 7 remaining digits.
Step5: Calculate the total number of codes
Using the multiplication principle, the total number of codes is \(9\times9\times8\times7\).
for the probability problem:
Step1: Use the property of probability distribution
The sum of all probabilities \(P(x)\) in a probability distribution is 1. Let the missing probability be \(p\).
We know that \(0.05 + p+0.23 + 0.21+0.17 + 0.11+0.01=1\)
Step2: Solve for \(p\)
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