QUESTION IMAGE
Question
- if figure jkf is rotated 90 degrees clockwise, what quadrant will it be in?
- if figure jkf is rotated 90 degrees counterclockwise, what quadrant will it be in?
- if figure jkf is rotated 180 degrees clockwise, what quadrant will it be in?
- if figure jkf is rotated 180 degrees counterclockwise, what quadrant will it be in?
Step1: Determine the original quadrant
The figure \(JKF\) is in the first quadrant (where \(x>0,y > 0\)).
Step2: Analyze \(90^{\circ}\) clock - wise rotation
When a point \((x,y)\) is rotated \(90^{\circ}\) clock - wise about the origin, the transformation rule is \((x,y)\to(y, - x)\). Points in the first quadrant \((x>0,y>0)\) will be mapped to the fourth quadrant (\(y>0,-x < 0\) is not correct, actually \((x,y)\to(y,-x)\), for positive \(x\) and \(y\), \(y>0\) and \(-x<0\), so the new points will be in the fourth quadrant).
Step3: Analyze \(90^{\circ}\) counter - clockwise rotation
When a point \((x,y)\) is rotated \(90^{\circ}\) counter - clockwise about the origin, the transformation rule is \((x,y)\to(-y,x)\). Points in the first quadrant \((x > 0,y>0)\) will be mapped to the second quadrant (\(-y<0,x>0\)).
Step4: Analyze \(180^{\circ}\) rotation (clockwise or counter - clockwise)
When a point \((x,y)\) is rotated \(180^{\circ}\) about the origin (clockwise or counter - clockwise, since \(180^{\circ}\) clockwise rotation \((x,y)\to(-x,-y)\) and \(180^{\circ}\) counter - clockwise rotation \((x,y)\to(-x,-y)\)), points in the first quadrant \((x>0,y>0)\) will be mapped to the third quadrant (\(-x<0,-y < 0\)).
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