Question

in the figure below, m ∠3 = 144°. find m ∠1, m ∠2, and m ∠4.

m ∠1 = \\(\square\\)°
m ∠2 = \\(\square\\)°
m ∠4 = \\(\square\\)°

Explanation:

Step1: Find m∠1 (vertical to ∠3)

Vertical angles are equal, so $m\angle1 = m\angle3 = 144^\circ$.

Step2: Find m∠2 (supplementary to ∠3)

Linear pair sums to $180^\circ$, so $m\angle2 = 180^\circ - 144^\circ = 36^\circ$.

Step3: Find m∠4 (vertical to ∠2)

Vertical angles are equal, so $m\angle4 = m\angle2 = 36^\circ$.

Answer:

$m\angle1 = 144^\circ$
$m\angle2 = 36^\circ$
$m\angle4 = 36^\circ$