Question

factoring day 5 (more
14x² + 12x − 2

3x³ − 16x² + 20x
x(3x² - 16x + 20)

7x² − 20x + 12

Explanation:

Step1: Factor out GCF first

$14x^2 +12x -2 = 2(7x^2 +6x -1)$

Step2: Factor quadratic

$7x^2 +6x -1 = (7x-1)(x+1)$, so $2(7x-1)(x+1)$
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Step1: Factor out GCF first

$3x^3 -16x^2 +20x = x(3x^2 -16x +20)$

Step2: Factor quadratic

$3x^2 -16x +20 = (3x-10)(x-2)$, so $x(3x-10)(x-2)$
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Step1: Factor the quadratic directly

$7x^2 -20x +12 = (7x-6)(x-2)$

Answer:

1. $2(7x-1)(x+1)$
2. $x(3x-10)(x-2)$
3. $(7x-6)(x-2)$