Question

factor out the common monomial factor y.
$x^{2}y - 9xy^{2} + y^{3} = y \cdot \left( \square \
ight)$

Explanation:

Step1: Factor y from first term

$\frac{x^2y}{y} = x^2$

Step2: Factor y from second term

$\frac{-9xy^2}{y} = -9xy$

Step3: Factor y from third term

$\frac{y^3}{y} = y^2$

Step4: Combine the results

$x^2 - 9xy + y^2$

Answer:

$x^2 - 9xy + y^2$