Question

factor by grouping.\\(2w^{3}+7w^{2}+4w + 14\\)

Explanation:

Step1: Group terms into pairs

$(2w^3 + 7w^2) + (4w + 14)$

Step2: Factor out GCF from each pair

$w^2(2w + 7) + 2(2w + 7)$

Step3: Factor out common binomial

$(2w + 7)(w^2 + 2)$

Answer:

$(2w + 7)(w^2 + 2)$