Question

factor by grouping.
2v³ + 5v² + 4v + 10

Explanation:

Step1: Group the terms

Group the first two terms and the last two terms: $(2v^3 + 5v^2) + (4v + 10)$

Step2: Factor out GCF from each group

Factor out $v^2$ from the first group and 2 from the second group: $v^2(2v + 5) + 2(2v + 5)$

Step3: Factor out the common binomial

Factor out $(2v + 5)$: $(2v + 5)(v^2 + 2)$

Answer:

$(2v + 5)(v^2 + 2)$