Question

factor completely. $6h^{3}-3h^{2}-16h + 8$

Explanation:

Step1: Group the terms

Group the first two terms and the last two terms: $(6h^3 - 3h^2) + (-16h + 8)$

Step2: Factor out GCF from each group

Factor out $3h^2$ from the first group and $-8$ from the second group: $3h^2(2h - 1) - 8(2h - 1)$

Step3: Factor out the common binomial

Factor out $(2h - 1)$: $(3h^2 - 8)(2h - 1)$

Answer:

$(3h^2 - 8)(2h - 1)$