Question

expand the expression to a polynomial in standard form:
$(3x + 1)(2x^2 - 2x - 9)$
answer
attempt 1 out of 2

Explanation:

Step1: Distribute $3x$ to each term

$3x \cdot 2x^2 + 3x \cdot (-2x) + 3x \cdot (-9) = 6x^3 - 6x^2 - 27x$

Step2: Distribute $1$ to each term

$1 \cdot 2x^2 + 1 \cdot (-2x) + 1 \cdot (-9) = 2x^2 - 2x - 9$

Step3: Combine like terms

$6x^3 + (-6x^2 + 2x^2) + (-27x - 2x) + (-9) = 6x^3 - 4x^2 - 29x - 9$

Answer:

$6x^3 - 4x^2 - 29x - 9$