expand the expression to a polynomial in standard form: (3x + 1)(2x - 1)(3x - 2)

Question

Accepted Answer

# Explanation:
## Step1: Multiply the first two binomials
First, multiply $(3x + 1)$ and $(2x - 1)$ using the distributive property (FOIL method):
$$
\begin{align*}
(3x + 1)(2x - 1)&=3x\times2x+3x\times(-1)+1\times2x + 1\times(-1)\
&=6x^{2}-3x + 2x-1\
&=6x^{2}-x - 1
\end{align*}
$$
## Step2: Multiply the result by the third binomial
Now, multiply $6x^{2}-x - 1$ by $(3x - 2)$:
$$
\begin{align*}
&(6x^{2}-x - 1)(3x - 2)\
&=6x^{2}\times3x+6x^{2}\times(-2)-x\times3x - x\times(-2)-1\times3x-1\times(-2)\
&=18x^{3}-12x^{2}-3x^{2}+2x - 3x + 2\
&=18x^{3}+(-12x^{2}-3x^{2})+(2x - 3x)+2\
&=18x^{3}-15x^{2}-x + 2
\end{align*}
$$
# Answer:
$18x^{3}-15x^{2}-x + 2$

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QUESTION IMAGE

Question

Explanation:

Step1: Multiply the first two binomials

Step2: Multiply the result by the third binomial

Answer: