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in exercises 9 and 10, use a compass and straightedge to construct a li…

Question

in exercises 9 and 10, use a compass and straightedge to construct a line through point p that is parallel to line m.
9.
p
m
10.
p
m
proving a theorem in exercises 11 and 12, prove the theorem. (see example 2.)

  1. alternate exterior angles converse (theorem 3.7)
  2. consecutive interior angles converse (theorem 3.8)

Explanation:

Step1: Identify the construction method

To construct a line through \( P \) parallel to \( m \), we use the "corresponding angles" or "copying an angle" method with compass and straightedge. First, draw a transversal (a line) through \( P \) and intersecting \( m \) at a point, say \( Q \).

Step2: Copy the angle

Using the compass, measure the angle formed between the transversal and \( m \) at \( Q \). Then, with \( P \) as the vertex, construct an angle equal to that measured angle on the transversal through \( P \). The side of this new angle will be the line parallel to \( m \) through \( P \).

Step3: Verify (optional for construction)

Visually check that the constructed line has the same slope (direction) as \( m \) and does not intersect \( m \) (since they are parallel).

For example, in problem 9:

  • Draw a transversal from \( P \) to intersect \( m \) at a point \( Q \).
  • Measure \( \angle PQM \) (where \( M \) is a point on \( m \)) with the compass.
  • At \( P \), construct \( \angle QPR \) equal to \( \angle PQM \), so line \( PR \) is parallel to \( m \).

(Note: The actual construction involves precise compass and straightedge steps, but the key is using angle - copying to ensure parallelism via equal corresponding angles, which is based on the converse of the corresponding angles theorem.)

Answer:

The construction involves drawing a transversal through \( P \) and \( m \), copying the angle formed by the transversal and \( m \) at the intersection point to \( P \), and the resulting line through \( P \) is parallel to \( m \). (The final constructed line is parallel to \( m \) through \( P \), and its exact drawing follows the compass - straightedge angle - copying method.)