Question

exam lesson name: motion and forces
exam number: 700696rr
exam guidelines
exam instructions
question 18 of 20 :
select the best answer for the question.

1. whats the velocity of an object that has a momentum of 4,000 kg-m/s and a mass of 115 kg? round to the nearest hundredth.

a. 37.43 m/s
b. 34.78 m/s
c. 35.67 m/s
d. 36.5 m/s
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Explanation:

Step1: Recall momentum formula

The formula for momentum \( p \) is \( p = mv \), where \( m \) is mass and \( v \) is velocity. We need to solve for \( v \), so rearrange the formula to \( v=\frac{p}{m} \).

Step2: Substitute values

Given \( p = 4000 \, \text{kg - m/s} \) and \( m = 115 \, \text{kg} \), substitute into the formula: \( v=\frac{4000}{115} \).

Step3: Calculate and round

Calculate \( \frac{4000}{115}\approx34.7826 \), round to the nearest hundredth gives \( 34.78 \, \text{m/s} \).

Answer:

B. 34.78 m/s