Question

exam 15
geometry
question 1: standard g.gmd.4
what is the best definition of a horizontal cross section?
a. slicing from top to bottom of a 3d shape to create a 2d cross section
b. slicing from left to right of a 3d shape to create a 2d cross section
c. reflecting a shape across the x axis
d. reflecting a shape across the y axis
question 2: standard g.gmd.4
what is the best definition of a vertical cross section?
a. slicing from top to bottom of a 3d shape to create a 2d cross section
b. slicing from left to right of a 3d shape to create a 2d cross section
c. reflecting a shape across the x axis
d. reflecting a shape across the y axis
question 3: standard g.gmd.4
if we rotate this shape around the line, what 3d shape does it become?
image of a right triangle with legs 9 cm and 5 cm, right - angled at the bottom right, with a vertical line on the right side of the triangle
a. cylinder
b. square based prism
c. cone
d. sphere
question 4: standard g.gmd.4
if we rotate this shape around the line, what 3d shape does it become?
image of a rectangle with length 5 in and height 2 in, sitting on a curved line
a. cylinder
b. square prism
c. sphere
d. cone

Explanation:

Question 1

A horizontal cross - section is created by slicing a 3D shape from left to right (perpendicular to the vertical axis) to get a 2D figure. Option a is vertical slicing, options c and d are about reflections, not cross - sections.

A vertical cross - section is made by slicing a 3D shape from top to bottom (parallel to the vertical axis) to form a 2D figure. Options b, c, d are either horizontal slicing (b) or reflections (c, d), not vertical cross - section.

When a right - triangle is rotated around one of its legs (the vertical line in the diagram), it forms a cone. A cylinder is formed by rotating a rectangle, a square - based prism is a type of rectangular prism, and a sphere is formed by rotating a semicircle. The given shape is a right - triangle, so rotating it around the leg will give a cone.

Answer:

b. Slicing from left to right of a 3D shape to create a 2D cross section

Question 2