Question

event a occurs with probability 0.4. event b occurs with probability 0.5. if a and b are disjoint (mutually exclusive), then... p(a or b)=0.5 p(a or b)=0.9 p(a and b)=0.3 p(a and b)=0.2

Explanation:

Step1: Recall the formula for mutually exclusive events

For mutually exclusive events \(A\) and \(B\), \(P(A\cap B)=0\) (since they cannot happen at the same time), and \(P(A\cup B)=P(A)+P(B)\).

Step2: Calculate \(P(A\cup B)\)

Given \(P(A) = 0.4\) and \(P(B)=0.5\), then \(P(A\cup B)=0.4 + 0.5\).

$$P(A\cup B)=0.9$$

Answer:

\(P(A\ or\ B)=0.9\)