Question

evaluate \\(6 + \frac{4}{a} + \frac{b}{3}\\) when \\(a = 4\\) and \\(b = 3\\).

Explanation:

Substitute the given values

$$ \text{Substitute } a = 4 \text{ and } b = 3 \text{ into } 6 + \frac{4}{a} + \frac{b}{3}: $$

$$ 6 + \frac{4}{4} + \frac{3}{3} $$

Simplify the fractions

$$ \frac{4}{4} = 1 $$

$$ \frac{3}{3} = 1 $$

Calculate the final sum

$$ 6 + 1 + 1 = 8 $$

Answer:

8