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evaluate $x = mu+zsigma$ if $mu = 38.9$, $z=-4.91$, and $sigma = 9.2$. …

Question

evaluate $x = mu+zsigma$ if $mu = 38.9$, $z=-4.91$, and $sigma = 9.2$.
$x=square$
(type an integer or decimal. do not round.)

Explanation:

Step1: Substitute the given values into the formula

Given the formula \(x = \mu+z\sigma\), substitute \(\mu = 38.9\), \(z=-4.91\), and \(\sigma = 9.2\) into it. So we have \(x=38.9+(-4.91)\times9.2\).

Step2: Calculate the product

First, calculate \((-4.91)\times9.2\). Using the rule of multiplying a negative number and a positive number (\(a\times(-b)=-(a\times b)\)), we get \((-4.91)\times9.2=-45.172\).

Step3: Calculate the sum

Now, calculate \(38.9+(-45.172)\). According to the rule \(a + (-b)=a - b\), we have \(38.9-45.172=-6.272\).

Answer:

\(-6.272\)