QUESTION IMAGE
Question
3 essay 10 points write a program that uses a loop to read 5 numbers from the user and prints their average.
Step1: Initialize variables
We need to initialize a variable to store the sum of the numbers (let's call it total) and a variable to keep track of the count of numbers (let's call it count). We'll start with total = 0 and count = 0.
Step2: Use a loop to read numbers
We can use a for loop that runs 5 times. In each iteration, we'll prompt the user to enter a number, convert it to a numeric type (e.g., float or int), add it to the total, and increment the count by 1. For example, in Python:
total = 0
count = 0
for _ in range(5):
num = float(input("Enter a number: "))
total += num
count += 1
Step3: Calculate the average
The average is calculated by dividing the total by the count. So, average = total / count.
Step4: Print the average
We'll print the calculated average. In Python, we can do print("The average is", average).
Putting it all together in Python:
total = 0
count = 0
for _ in range(5):
num = float(input("Enter a number: "))
total += num
count += 1
average = total / count
print("The average is", average)
If we were to use a different programming language like Java, the code would be:
import java.util.Scanner;
public class AverageCalculator {
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
double total = 0;
int count = 0;
for (int i = 0; i < 5; i++) {
System.out.print("Enter a number: ");
double num = scanner.nextDouble();
total += num;
count++;
}
double average = total / count;
System.out.println("The average is " + average);
scanner.close();
}
}Snap & solve any problem in the app
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Here is a Python program to solve the problem:
total = 0
count = 0
for _ in range(5):
num = float(input("Enter a number: "))
total += num
count += 1
average = total / count
print("The average is", average)
(Or the equivalent program in your preferred programming language following the same logic of reading 5 numbers, summing them, and dividing by 5 to get the average.)