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equivalent ratios show two sets of numbers that have the same proportio…

Question

equivalent ratios show two sets of numbers that have the same proportional relationship. they are found by expanding or simplifying a ratio like a fraction.
circle the ratio that is not equivalent.
a. 32:42 4:6 60:90
b. 1:2 12:26 16:32
c. 4:3 15:10 20:15
d. 10:4 25:10 50:44
e. 2:6 12:32 3:8
f. 3:14 6:21 2:7
g. 22:18 11:9 100:60
h. 3:1 9:3 15:6
i. 8:10 10:12 4:5

Explanation:

Step1: Simplify each ratio

For ratio \(a. 32:42\), divide both by \(2\) to get \(\frac{32\div2}{42\div2}=\frac{16}{21}\).
For ratio \(b. 1:2\), it is already in simplest form.
For ratio \(c. 4:3\), it is already in simplest form.
For ratio \(d. 10:4 = 25:10 = 50:44\), simplify \(10:4=\frac{10\div2}{4\div2}=\frac{5}{2}\), \(25:10=\frac{25\div5}{10\div5}=\frac{5}{2}\), \(50:44=\frac{50\div2}{44\div2}=\frac{25}{22}\).
For ratio \(e. 2:6 = 12:32 = 3:8\), simplify \(2:6=\frac{2\div2}{6\div2}=\frac{1}{3}\), \(12:32=\frac{12\div4}{32\div4}=\frac{3}{8}\), \(3:8\) is already in simplest form.
For ratio \(f. 3:14 = 6:21 = 2:7\), simplify \(3:14\) (already in simplest form), \(6:21=\frac{6\div3}{21\div3}=\frac{2}{7}\), \(2:7\) is already in simplest form.
For ratio \(g. 22:18 = 11:9 = 100:90\), simplify \(22:18=\frac{22\div2}{18\div2}=\frac{11}{9}\), \(11:9\) is already in simplest form, \(100:90=\frac{100\div10}{90\div10}=\frac{10}{9}\).
For ratio \(h. 3:1 = 9:3\), \(3:1\) is already in simplest form, \(9:3=\frac{9\div3}{3\div3}=3:1\).
For ratio \(i. 8:10 = 10:12 = 4:5\), simplify \(8:10=\frac{8\div2}{10\div2}=\frac{4}{5}\), \(10:12=\frac{10\div2}{12\div2}=\frac{5}{6}\), \(4:5\) is already in simplest form.

Answer:

The ratios that are not equivalent are \(a. 32:42\), \(b. 1:2\), \(c. 4:3\), \(d. 10:4 = 25:10 = 50:44\), \(e. 2:6 = 12:32 = 3:8\), \(f. 3:14 = 6:21 = 2:7\), \(g. 22:18 = 11:9 = 100:90\), \(h. 3:1 = 9:3\), \(i. 8:10 = 10:12 = 4:5\) (the circled ones in the original problem are the non - equivalent ones among the given pairs).