Question

the equilibrium constant has been determined in several reactions as follows: 1. $\ce{n_{2}(g) + o_{2}(g) \
ightarrow 2no(g)}$ $k_{eq} = 4.8 \times 10^{-31}$ 2. $\ce{h_{2}(g) + cl_{2}(g) \
ightarrow 2hcl(g)}$ $k_{eq} = 4.0 \times 10^{31}$ 3. $\ce{2co(g) + o_{2}(g) \
ightarrow 2co_{2}(g)}$ $k_{eq} = 2.3 \times 10^{22}$ 4. $\ce{cu(s) + 2ag^{+}(aq) \
ightarrow cu^{2+}(aq) + 2ag(s)}$ $k_{eq} = 2.0 \times 10^{15}$ the correct arrangement of the above reactions, in decreasing order of their ability to form products, is _______, _______, _______, and _______. $\bigcirc$ 1, 2, 4, 3 $\bigcirc$ 1, 4, 3, 2 $\bigcirc$ 2, 1, 3, 4 $\bigcirc$ 2, 3, 4, 1 $\bigcirc$ 3, 4, 2, 1

Explanation:

Step1: Recall \( K_{eq} \) meaning

A larger \( K_{eq} \) means the reaction favors products more (better at forming products).

Step2: Compare \( K_{eq} \) values

• Reaction 2: \( K_{eq} = 4.0 \times 10^{31} \)
• Reaction 3: \( K_{eq} = 2.3 \times 10^{22} \)
• Reaction 4: \( K_{eq} = 2.0 \times 10^{15} \)
• Reaction 1: \( K_{eq} = 4.8 \times 10^{-31} \)

Order from largest to smallest \( K_{eq} \):
Reaction 2 (\( 4.0 \times 10^{31} \)) > Reaction 3 (\( 2.3 \times 10^{22} \)) > Reaction 4 (\( 2.0 \times 10^{15} \)) > Reaction 1 (\( 4.8 \times 10^{-31} \))? Wait, no—wait the options: Wait the correct order by \( K_{eq} \) magnitude:

Wait, let's re - check the values:

Reaction 2: \( 4.0\times10^{31} \) (largest), Reaction 3: \( 2.3\times10^{22} \), Reaction 4: \( 2.0\times10^{15} \), Reaction 1: \( 4.8\times10^{-31} \) (smallest). But the option with 2,3,4,1? Wait no, the option "2, 3, 4, 1" would be correct? Wait no, the user's selected option was wrong? Wait no, let's re - evaluate:

Wait the problem says "decreasing order of their ability to form products"—higher \( K_{eq} \) means better at forming products.

So:

Reaction 2: \( 4.0\times10^{31} \) (highest)

Reaction 3: \( 2.3\times10^{22} \)

Reaction 4: \( 2.0\times10^{15} \)

Reaction 1: \( 4.8\times10^{-31} \) (lowest)

So order: 2, 3, 4, 1. But the user's selected option was 3,4,2,1 which is wrong. Wait, maybe I misread the reactions. Let's re - check the reactions:

Reaction 1: \( N_2 + O_2
ightarrow 2NO \), \( K = 4.8\times10^{-31} \)

Reaction 2: \( H_2 + Cl_2
ightarrow 2HCl \), \( K = 4.0\times10^{31} \)

Reaction 3: \( 2CO + O_2
ightarrow 2CO_2 \), \( K = 2.3\times10^{22} \)

Reaction 4: \( Cu + 2Ag^+
ightarrow Cu^{2+}+2Ag \), \( K = 2.0\times10^{15} \)

So the correct order (decreasing ability to form products) is Reaction 2 (highest \( K \)), then 3, then 4, then 1. So the correct option is "2, 3, 4, 1".

Answer:

2, 3, 4, 1 (i.e., the option with "2, 3, 4, 1")