Question

1. an equation is shown, where ( p < 0 ).

( pcdot q=r )
a. assume ( r > 0 ). plot a point on
b. assume ( r < 0 ). plot a point on
the number line to identify a
the number line to identify a
possible location for ( q ).
possible location for ( q ).

1. the total change in the outdoor temperature over 6 hours was ( -21^{circ} mathrm{f} ).

what was the mean change in temperature per hour?
( -3.5 quad{ }^{circ} mathrm{f} ) per hour

1. which expressions are equivalent to ( left(-\frac{1}{3}

ight)(-2)(6) ) ? select equivalent or
not equivalent for each expression.

1. the depth of water in a swimming pool decreases by ( \frac{1}{8} ) inch per day due to

evaporation. no water is added to the pool for a 2 -week period. what is
the total change in the depth of the water during this time period?
( -1 \frac{3}{4} ) inches
c ( 1 \frac{7}{8} ) inches
b ( -\frac{1}{4} ) inch
d 16 inches

1. which expression is equivalent to ( -left(\frac{2}{5}

ight) ) ?
(a) ( -\frac{(-2)}{5} )
(b) ( -\frac{2}{(-5)} )
(c) ( \frac{-2}{-5} )
( \frac{2}{-5} )

1. which decimal is equivalent to ( \frac{5}{9} ) ?

0.5
b 0.55
c 1.8
d 5.9

Explanation:

Step1: Calculate the mean change in temperature

The formula for the mean (average) is \(\text{Mean}=\frac{\text{Total change}}{\text{Number of hours}}\).
We are given that the total change in temperature is \(- 21^{\circ}\text{F}\) and the number of hours is \(6\).
So, \(\text{Mean}=\frac{-21}{6}\).

Step2: Simplify the fraction

\(\frac{-21}{6}=\frac{-21\div3}{6\div3}=\frac{-7}{2}=-3.5\)

Answer:

\(-3.5^{\circ}\text{F}\) per hour