Question

ep by step to reduce the radical.
\sqrt{32}
\sqrt{16} \cdot \sqrt{2}
\square \sqrt{\square}
try

Explanation:

Step1: Factor 32 into perfect square

$\sqrt{32} = \sqrt{16 \times 2}$

Step2: Split radical using product rule

$\sqrt{16 \times 2} = \sqrt{16} \cdot \sqrt{2}$

Step3: Simplify $\sqrt{16}$

$\sqrt{16} = 4$

Answer:

$4\sqrt{2}$