Question

ent to the circle centered at o. given that $oq = 9.9$ and $op = 16.5$, find $pr$.

Explanation:

Step1: Use the Pythagorean theorem

Since \(PQ\) is tangent to the circle at \(Q\), \(OQ\perp PQ\). In right - triangle \(OQP\), by the Pythagorean theorem \(PQ=\sqrt{OP^{2}-OQ^{2}}\). Substitute \(OQ = 9.9\) and \(OP = 16.5\) into the formula:

$$
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Step2: Use the property of tangent segments

If two tangent segments are drawn from an external point \(P\) to a circle, then the two tangent segments are equal. So \(PQ=PR\)

Answer:

\(13.2\)